Sparse data structures#

pandas provides data structures for efficiently storing sparse data. These are not necessarily sparse in the typical “mostly 0”. Rather, you can view these objects as being “compressed” where any data matching a specific value (NaN / missing value, though any value can be chosen, including 0) is omitted. The compressed values are not actually stored in the array.

In [1]: arr = np.random.randn(10)

In [2]: arr[2:-2] = np.nan

In [3]: ts = pd.Series(pd.arrays.SparseArray(arr))

In [4]: ts
Out[4]: 
0    0.469112
1   -0.282863
2         NaN
3         NaN
4         NaN
5         NaN
6         NaN
7         NaN
8   -0.861849
9   -2.104569
dtype: Sparse[float64, nan]

Notice the dtype, Sparse[float64, nan]. The nan means that elements in the array that are nan aren’t actually stored, only the non-nan elements are. Those non-nan elements have a float64 dtype.

The sparse objects exist for memory efficiency reasons. Suppose you had a large, mostly NA DataFrame:

In [5]: df = pd.DataFrame(np.random.randn(10000, 4))

In [6]: df.iloc[:9998] = np.nan

In [7]: sdf = df.astype(pd.SparseDtype("float", np.nan))

In [8]: sdf.head()
Out[8]: 
     0    1    2    3
0  NaN  NaN  NaN  NaN
1  NaN  NaN  NaN  NaN
2  NaN  NaN  NaN  NaN
3  NaN  NaN  NaN  NaN
4  NaN  NaN  NaN  NaN

In [9]: sdf.dtypes
Out[9]: 
0    Sparse[float64, nan]
1    Sparse[float64, nan]
2    Sparse[float64, nan]
3    Sparse[float64, nan]
dtype: object

In [10]: sdf.sparse.density
Out[10]: 0.0002

As you can see, the density (% of values that have not been “compressed”) is extremely low. This sparse object takes up much less memory on disk (pickled) and in the Python interpreter.

In [11]: 'dense : {:0.2f} bytes'.format(df.memory_usage().sum() / 1e3)
Out[11]: 'dense : 320.13 bytes'

In [12]: 'sparse: {:0.2f} bytes'.format(sdf.memory_usage().sum() / 1e3)
Out[12]: 'sparse: 0.22 bytes'

Functionally, their behavior should be nearly identical to their dense counterparts.

SparseArray#

arrays.SparseArray is a ExtensionArray for storing an array of sparse values (see dtypes for more on extension arrays). It is a 1-dimensional ndarray-like object storing only values distinct from the fill_value:

In [13]: arr = np.random.randn(10)

In [14]: arr[2:5] = np.nan

In [15]: arr[7:8] = np.nan

In [16]: sparr = pd.arrays.SparseArray(arr)

In [17]: sparr
Out[17]: 
[-1.9556635297215477, -1.6588664275960427, nan, nan, nan, 1.1589328886422277, 0.14529711373305043, nan, 0.6060271905134522, 1.3342113401317768]
Fill: nan
IntIndex
Indices: array([0, 1, 5, 6, 8, 9], dtype=int32)

A sparse array can be converted to a regular (dense) ndarray with numpy.asarray()

In [18]: np.asarray(sparr)
Out[18]: 
array([-1.9557, -1.6589,     nan,     nan,     nan,  1.1589,  0.1453,
           nan,  0.606 ,  1.3342])

SparseDtype#

The SparseArray.dtype property stores two pieces of information

  1. The dtype of the non-sparse values

  2. The scalar fill value

In [19]: sparr.dtype
Out[19]: Sparse[float64, nan]

A SparseDtype may be constructed by passing only a dtype

In [20]: pd.SparseDtype(np.dtype('datetime64[ns]'))
Out[20]: Sparse[datetime64[ns], numpy.datetime64('NaT')]

in which case a default fill value will be used (for NumPy dtypes this is often the “missing” value for that dtype). To override this default an explicit fill value may be passed instead

In [21]: pd.SparseDtype(np.dtype('datetime64[ns]'),
   ....:                fill_value=pd.Timestamp('2017-01-01'))
   ....: 
Out[21]: Sparse[datetime64[ns], Timestamp('2017-01-01 00:00:00')]

Finally, the string alias 'Sparse[dtype]' may be used to specify a sparse dtype in many places

In [22]: pd.array([1, 0, 0, 2], dtype='Sparse[int]')
Out[22]: 
[1, 0, 0, 2]
Fill: 0
IntIndex
Indices: array([0, 3], dtype=int32)

Sparse accessor#

pandas provides a .sparse accessor, similar to .str for string data, .cat for categorical data, and .dt for datetime-like data. This namespace provides attributes and methods that are specific to sparse data.

In [23]: s = pd.Series([0, 0, 1, 2], dtype="Sparse[int]")

In [24]: s.sparse.density
Out[24]: 0.5

In [25]: s.sparse.fill_value
Out[25]: 0

This accessor is available only on data with SparseDtype, and on the Series class itself for creating a Series with sparse data from a scipy COO matrix with.

A .sparse accessor has been added for DataFrame as well. See Sparse accessor for more.

Sparse calculation#

You can apply NumPy ufuncs to arrays.SparseArray and get a arrays.SparseArray as a result.

In [26]: arr = pd.arrays.SparseArray([1., np.nan, np.nan, -2., np.nan])

In [27]: np.abs(arr)
Out[27]: 
[1.0, nan, nan, 2.0, nan]
Fill: nan
IntIndex
Indices: array([0, 3], dtype=int32)

The ufunc is also applied to fill_value. This is needed to get the correct dense result.

In [28]: arr = pd.arrays.SparseArray([1., -1, -1, -2., -1], fill_value=-1)

In [29]: np.abs(arr)
Out[29]: 
[1, 1, 1, 2.0, 1]
Fill: 1
IntIndex
Indices: array([3], dtype=int32)

In [30]: np.abs(arr).to_dense()
Out[30]: array([1., 1., 1., 2., 1.])

Conversion

To convert data from sparse to dense, use the .sparse accessors

In [31]: sdf.sparse.to_dense()
Out[31]: 
             0         1         2         3
0          NaN       NaN       NaN       NaN
1          NaN       NaN       NaN       NaN
2          NaN       NaN       NaN       NaN
3          NaN       NaN       NaN       NaN
4          NaN       NaN       NaN       NaN
...        ...       ...       ...       ...
9995       NaN       NaN       NaN       NaN
9996       NaN       NaN       NaN       NaN
9997       NaN       NaN       NaN       NaN
9998  0.509184 -0.774928 -1.369894 -0.382141
9999  0.280249 -1.648493  1.490865 -0.890819

[10000 rows x 4 columns]

From dense to sparse, use DataFrame.astype() with a SparseDtype.

In [32]: dense = pd.DataFrame({"A": [1, 0, 0, 1]})

In [33]: dtype = pd.SparseDtype(int, fill_value=0)

In [34]: dense.astype(dtype)
Out[34]: 
   A
0  1
1  0
2  0
3  1

Interaction with scipy.sparse#

Use DataFrame.sparse.from_spmatrix() to create a DataFrame with sparse values from a sparse matrix.

In [35]: from scipy.sparse import csr_matrix

In [36]: arr = np.random.random(size=(1000, 5))

In [37]: arr[arr < .9] = 0

In [38]: sp_arr = csr_matrix(arr)

In [39]: sp_arr
Out[39]: 
<Compressed Sparse Row sparse matrix of dtype 'float64'
	with 517 stored elements and shape (1000, 5)>

In [40]: sdf = pd.DataFrame.sparse.from_spmatrix(sp_arr)

In [41]: sdf.head()
Out[41]: 
          0  1  2         3  4
0   0.95638  0  0         0  0
1         0  0  0         0  0
2         0  0  0         0  0
3         0  0  0         0  0
4  0.999552  0  0  0.956153  0

In [42]: sdf.dtypes
Out[42]: 
0    Sparse[float64, 0]
1    Sparse[float64, 0]
2    Sparse[float64, 0]
3    Sparse[float64, 0]
4    Sparse[float64, 0]
dtype: object

All sparse formats are supported, but matrices that are not in COOrdinate format will be converted, copying data as needed. To convert back to sparse SciPy matrix in COO format, you can use the DataFrame.sparse.to_coo() method:

In [43]: sdf.sparse.to_coo()
Out[43]: 
<COOrdinate sparse matrix of dtype 'float64'
	with 517 stored elements and shape (1000, 5)>

Series.sparse.to_coo() is implemented for transforming a Series with sparse values indexed by a MultiIndex to a scipy.sparse.coo_matrix.

The method requires a MultiIndex with two or more levels.

In [44]: s = pd.Series([3.0, np.nan, 1.0, 3.0, np.nan, np.nan])

In [45]: s.index = pd.MultiIndex.from_tuples(
   ....:     [
   ....:         (1, 2, "a", 0),
   ....:         (1, 2, "a", 1),
   ....:         (1, 1, "b", 0),
   ....:         (1, 1, "b", 1),
   ....:         (2, 1, "b", 0),
   ....:         (2, 1, "b", 1),
   ....:     ],
   ....:     names=["A", "B", "C", "D"],
   ....: )
   ....: 

In [46]: ss = s.astype('Sparse')

In [47]: ss
Out[47]: 
A  B  C  D
1  2  a  0    3.0
         1    NaN
   1  b  0    1.0
         1    3.0
2  1  b  0    NaN
         1    NaN
dtype: Sparse[float64, nan]

In the example below, we transform the Series to a sparse representation of a 2-d array by specifying that the first and second MultiIndex levels define labels for the rows and the third and fourth levels define labels for the columns. We also specify that the column and row labels should be sorted in the final sparse representation.

In [48]: A, rows, columns = ss.sparse.to_coo(
   ....:     row_levels=["A", "B"], column_levels=["C", "D"], sort_labels=True
   ....: )
   ....: 

In [49]: A
Out[49]: 
<COOrdinate sparse matrix of dtype 'float64'
	with 3 stored elements and shape (3, 4)>

In [50]: A.todense()
Out[50]: 
matrix([[0., 0., 1., 3.],
        [3., 0., 0., 0.],
        [0., 0., 0., 0.]])

In [51]: rows
Out[51]: [(1, 1), (1, 2), (2, 1)]

In [52]: columns
Out[52]: [('a', 0), ('a', 1), ('b', 0), ('b', 1)]

Specifying different row and column labels (and not sorting them) yields a different sparse matrix:

In [53]: A, rows, columns = ss.sparse.to_coo(
   ....:     row_levels=["A", "B", "C"], column_levels=["D"], sort_labels=False
   ....: )
   ....: 

In [54]: A
Out[54]: 
<COOrdinate sparse matrix of dtype 'float64'
	with 3 stored elements and shape (3, 2)>

In [55]: A.todense()
Out[55]: 
matrix([[3., 0.],
        [1., 3.],
        [0., 0.]])

In [56]: rows
Out[56]: [(1, 2, 'a'), (1, 1, 'b'), (2, 1, 'b')]

In [57]: columns
Out[57]: [(0,), (1,)]

A convenience method Series.sparse.from_coo() is implemented for creating a Series with sparse values from a scipy.sparse.coo_matrix.

In [58]: from scipy import sparse

In [59]: A = sparse.coo_matrix(([3.0, 1.0, 2.0], ([1, 0, 0], [0, 2, 3])), shape=(3, 4))

In [60]: A
Out[60]: 
<COOrdinate sparse matrix of dtype 'float64'
	with 3 stored elements and shape (3, 4)>

In [61]: A.todense()
Out[61]: 
matrix([[0., 0., 1., 2.],
        [3., 0., 0., 0.],
        [0., 0., 0., 0.]])

The default behaviour (with dense_index=False) simply returns a Series containing only the non-null entries.

In [62]: ss = pd.Series.sparse.from_coo(A)

In [63]: ss
Out[63]: 
0  2    1.0
   3    2.0
1  0    3.0
dtype: Sparse[float64, nan]

Specifying dense_index=True will result in an index that is the Cartesian product of the row and columns coordinates of the matrix. Note that this will consume a significant amount of memory (relative to dense_index=False) if the sparse matrix is large (and sparse) enough.

In [64]: ss_dense = pd.Series.sparse.from_coo(A, dense_index=True)

In [65]: ss_dense
Out[65]: 
1  0    3.0
   2    NaN
   3    NaN
0  0    NaN
   2    1.0
   3    2.0
   0    NaN
   2    1.0
   3    2.0
dtype: Sparse[float64, nan]