pandas.core.groupby.GroupBy.ngroup

GroupBy.ngroup(self, ascending=True)[source]

Number each group from 0 to the number of groups - 1.

This is the enumerative complement of cumcount. Note that the numbers given to the groups match the order in which the groups would be seen when iterating over the groupby object, not the order they are first observed.

New in version 0.20.2.

Parameters:
ascending : bool, default True

If False, number in reverse, from number of group - 1 to 0.

Returns:
Series

Unique numbers for each group.

See also

cumcount
Number the rows in each group.

Examples

>>> df = pd.DataFrame({"A": list("aaabba")})
>>> df
   A
0  a
1  a
2  a
3  b
4  b
5  a
>>> df.groupby('A').ngroup()
0    0
1    0
2    0
3    1
4    1
5    0
dtype: int64
>>> df.groupby('A').ngroup(ascending=False)
0    1
1    1
2    1
3    0
4    0
5    1
dtype: int64
>>> df.groupby(["A", [1,1,2,3,2,1]]).ngroup()
0    0
1    0
2    1
3    3
4    2
5    0
dtype: int64
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