pandas.IntervalIndex.get_loc

IntervalIndex.get_loc(self, key: Any, method: Union[str, NoneType] = None, tolerance=None) → Union[int, slice, numpy.ndarray][source]

Get integer location, slice or boolean mask for requested label.

Parameters
keylabel
method{None}, optional

  • default: matches where the label is within an interval only.

Returns
int if unique index, slice if monotonic index, else mask

Examples

>>> i1, i2 = pd.Interval(0, 1), pd.Interval(1, 2)
>>> index = pd.IntervalIndex([i1, i2])
>>> index.get_loc(1)
0

You can also supply a point inside an interval.

>>> index.get_loc(1.5)
1

If a label is in several intervals, you get the locations of all the relevant intervals.

>>> i3 = pd.Interval(0, 2)
>>> overlapping_index = pd.IntervalIndex([i1, i2, i3])
>>> overlapping_index.get_loc(0.5)
array([ True, False,  True])

Only exact matches will be returned if an interval is provided.

>>> index.get_loc(pd.Interval(0, 1))
0
pandas.IntervalIndex.to_tuples pandas.IntervalIndex.get_indexer