pandas.TimedeltaIndex.slice_locs

TimedeltaIndex.slice_locs(start=None, end=None, step=None, kind=None)

Compute slice locations for input labels.

Parameters:

start : label, default None

If None, defaults to the beginning

end : label, default None

If None, defaults to the end

step : int, defaults None

If None, defaults to 1

kind : {‘ix’, ‘loc’, ‘getitem’} or None

Returns:

start, end : int

See also

Index.get_loc

Get location for a single label

Notes

This method only works if the index is monotonic or unique.

Examples

>>> idx = pd.Index(list('abcd'))
>>> idx.slice_locs(start='b', end='c')
(1, 3)