pandas.Series.str.rpartition¶
-
Series.str.
rpartition
(sep=' ', expand=True)[source]¶ Split the string at the last occurrence of sep.
This method splits the string at the last occurrence of sep, and returns 3 elements containing the part before the separator, the separator itself, and the part after the separator. If the separator is not found, return 3 elements containing two empty strings, followed by the string itself.
Parameters: - sep : str, default whitespace
String to split on.
- pat : str, default whitespace
Deprecated since version 0.24.0: Use
sep
instead- expand : bool, default True
If True, return DataFrame/MultiIndex expanding dimensionality. If False, return Series/Index.
Returns: - DataFrame/MultiIndex or Series/Index of objects
See also
partition
- Split the string at the first occurrence of sep.
Series.str.split
- Split strings around given separators.
str.partition
- Standard library version.
Examples
>>> s = pd.Series(['Linda van der Berg', 'George Pitt-Rivers']) >>> s 0 Linda van der Berg 1 George Pitt-Rivers dtype: object
>>> s.str.partition() 0 1 2 0 Linda van der Berg 1 George Pitt-Rivers
To partition by the last space instead of the first one:
>>> s.str.rpartition() 0 1 2 0 Linda van der Berg 1 George Pitt-Rivers
To partition by something different than a space:
>>> s.str.partition('-') 0 1 2 0 Linda van der Berg 1 George Pitt - Rivers
To return a Series containining tuples instead of a DataFrame:
>>> s.str.partition('-', expand=False) 0 (Linda van der Berg, , ) 1 (George Pitt, -, Rivers) dtype: object
Also available on indices:
>>> idx = pd.Index(['X 123', 'Y 999']) >>> idx Index(['X 123', 'Y 999'], dtype='object')
Which will create a MultiIndex:
>>> idx.str.partition() MultiIndex(levels=[['X', 'Y'], [' '], ['123', '999']], codes=[[0, 1], [0, 0], [0, 1]])
Or an index with tuples with
expand=False
:>>> idx.str.partition(expand=False) Index([('X', ' ', '123'), ('Y', ' ', '999')], dtype='object')