MultiIndex.
set_levels
Set new levels on MultiIndex. Defaults to returning new index.
New level(s) to apply.
Level(s) to set (None for all levels).
If True, mutates in place.
If True, checks that levels and codes are compatible.
Examples
>>> idx = pd.MultiIndex.from_tuples([(1, 'one'), (1, 'two'), (2, 'one'), (2, 'two'), (3, 'one'), (3, 'two')], names=['foo', 'bar']) >>> idx.set_levels([['a', 'b', 'c'], [1, 2]]) MultiIndex([('a', 1), ('a', 2), ('b', 1), ('b', 2), ('c', 1), ('c', 2)], names=['foo', 'bar']) >>> idx.set_levels(['a', 'b', 'c'], level=0) MultiIndex([('a', 'one'), ('a', 'two'), ('b', 'one'), ('b', 'two'), ('c', 'one'), ('c', 'two')], names=['foo', 'bar']) >>> idx.set_levels(['a', 'b'], level='bar') MultiIndex([(1, 'a'), (1, 'b'), (2, 'a'), (2, 'b'), (3, 'a'), (3, 'b')], names=['foo', 'bar'])
If any of the levels passed to set_levels() exceeds the existing length, all of the values from that argument will be stored in the MultiIndex levels, though the values will be truncated in the MultiIndex output.
set_levels()
>>> idx.set_levels([['a', 'b', 'c'], [1, 2, 3, 4]], level=[0, 1]) MultiIndex([('a', 1), ('a', 2), ('b', 1), ('b', 2)], names=['foo', 'bar']) >>> idx.set_levels([['a', 'b', 'c'], [1, 2, 3, 4]], level=[0, 1]).levels FrozenList([['a', 'b', 'c'], [1, 2, 3, 4]])