pandas.Index.equals

Index.equals(other)[source]

Determine if two Index object are equal.

The things that are being compared are:

  • The elements inside the Index object.

  • The order of the elements inside the Index object.

Parameters
otherAny

The other object to compare against.

Returns
bool

True if “other” is an Index and it has the same elements and order as the calling index; False otherwise.

Examples

>>> idx1 = pd.Index([1, 2, 3])
>>> idx1
Int64Index([1, 2, 3], dtype='int64')
>>> idx1.equals(pd.Index([1, 2, 3]))
True

The elements inside are compared

>>> idx2 = pd.Index(["1", "2", "3"])
>>> idx2
Index(['1', '2', '3'], dtype='object')
>>> idx1.equals(idx2)
False

The order is compared

>>> ascending_idx = pd.Index([1, 2, 3])
>>> ascending_idx
Int64Index([1, 2, 3], dtype='int64')
>>> descending_idx = pd.Index([3, 2, 1])
>>> descending_idx
Int64Index([3, 2, 1], dtype='int64')
>>> ascending_idx.equals(descending_idx)
False

The dtype is not compared

>>> int64_idx = pd.Index([1, 2, 3], dtype='int64')
>>> int64_idx
Int64Index([1, 2, 3], dtype='int64')
>>> uint64_idx = pd.Index([1, 2, 3], dtype='uint64')
>>> uint64_idx
UInt64Index([1, 2, 3], dtype='uint64')
>>> int64_idx.equals(uint64_idx)
True