pandas.Index.set_names¶
- Index.set_names(names, level=None, inplace=False)[source]¶
Set Index or MultiIndex name.
Able to set new names partially and by level.
- Parameters
- nameslabel or list of label or dict-like for MultiIndex
Name(s) to set.
Changed in version 1.3.0.
- levelint, label or list of int or label, optional
If the index is a MultiIndex and names is not dict-like, level(s) to set (None for all levels). Otherwise level must be None.
Changed in version 1.3.0.
- inplacebool, default False
Modifies the object directly, instead of creating a new Index or MultiIndex.
- Returns
- Index or None
The same type as the caller or None if
inplace=True
.
See also
Index.rename
Able to set new names without level.
Examples
>>> idx = pd.Index([1, 2, 3, 4]) >>> idx Int64Index([1, 2, 3, 4], dtype='int64') >>> idx.set_names('quarter') Int64Index([1, 2, 3, 4], dtype='int64', name='quarter')
>>> idx = pd.MultiIndex.from_product([['python', 'cobra'], ... [2018, 2019]]) >>> idx MultiIndex([('python', 2018), ('python', 2019), ( 'cobra', 2018), ( 'cobra', 2019)], ) >>> idx.set_names(['kind', 'year'], inplace=True) >>> idx MultiIndex([('python', 2018), ('python', 2019), ( 'cobra', 2018), ( 'cobra', 2019)], names=['kind', 'year']) >>> idx.set_names('species', level=0) MultiIndex([('python', 2018), ('python', 2019), ( 'cobra', 2018), ( 'cobra', 2019)], names=['species', 'year'])
When renaming levels with a dict, levels can not be passed.
>>> idx.set_names({'kind': 'snake'}) MultiIndex([('python', 2018), ('python', 2019), ( 'cobra', 2018), ( 'cobra', 2019)], names=['snake', 'year'])