pandas.Series.nlargest¶
- Series.nlargest(n=5, take_last=False)¶
Return the largest n elements.
Parameters: n : int
Return this many descending sorted values
take_last : bool
Where there are duplicate values, take the last duplicate
Returns: top_n : Series
The n largest values in the Series, in sorted order
See also
Notes
Faster than .order(ascending=False).head(n) for small n relative to the size of the Series object.
Examples
>>> import pandas as pd >>> import numpy as np >>> s = pd.Series(np.random.randn(1e6)) >>> s.nlargest(10) # only sorts up to the N requested