pandas.core.groupby.SeriesGroupBy.nlargest¶
- SeriesGroupBy.nlargest(*args, **kwargs)¶
Return the largest n elements.
Parameters: n : int
Return this many descending sorted values
keep : {‘first’, ‘last’, False}, default ‘first’
Where there are duplicate values: - first : take the first occurrence. - last : take the last occurrence.
take_last : deprecated
Returns: top_n : Series
The n largest values in the Series, in sorted order
See also
Series.nsmallest
Notes
Faster than .sort_values(ascending=False).head(n) for small n relative to the size of the Series object.
Examples
>>> import pandas as pd >>> import numpy as np >>> s = pd.Series(np.random.randn(1e6)) >>> s.nlargest(10) # only sorts up to the N requested