pandas.MultiIndex.set_codes¶
-
MultiIndex.
set_codes
(codes, level=None, inplace=False, verify_integrity=True)[source]¶ Set new codes on MultiIndex. Defaults to returning new index.
New in version 0.24.0: New name for deprecated method set_labels.
Parameters: - codes : sequence or list of sequence
new codes to apply
- level : int, level name, or sequence of int/level names (default None)
level(s) to set (None for all levels)
- inplace : bool
if True, mutates in place
- verify_integrity : bool (default True)
if True, checks that levels and codes are compatible
Returns: - new index (of same type and class…etc)
Examples
>>> idx = pd.MultiIndex.from_tuples([(1, u'one'), (1, u'two'), (2, u'one'), (2, u'two')], names=['foo', 'bar']) >>> idx.set_codes([[1,0,1,0], [0,0,1,1]]) MultiIndex(levels=[[1, 2], [u'one', u'two']], codes=[[1, 0, 1, 0], [0, 0, 1, 1]], names=[u'foo', u'bar']) >>> idx.set_codes([1,0,1,0], level=0) MultiIndex(levels=[[1, 2], [u'one', u'two']], codes=[[1, 0, 1, 0], [0, 1, 0, 1]], names=[u'foo', u'bar']) >>> idx.set_codes([0,0,1,1], level='bar') MultiIndex(levels=[[1, 2], [u'one', u'two']], codes=[[0, 0, 1, 1], [0, 0, 1, 1]], names=[u'foo', u'bar']) >>> idx.set_codes([[1,0,1,0], [0,0,1,1]], level=[0,1]) MultiIndex(levels=[[1, 2], [u'one', u'two']], codes=[[1, 0, 1, 0], [0, 0, 1, 1]], names=[u'foo', u'bar'])