pandas.MultiIndex.set_levels¶
-
MultiIndex.
set_levels
(levels, level=None, inplace=False, verify_integrity=True)[source]¶ Set new levels on MultiIndex. Defaults to returning new index.
Parameters: - levels : sequence or list of sequence
new level(s) to apply
- level : int, level name, or sequence of int/level names (default None)
level(s) to set (None for all levels)
- inplace : bool
if True, mutates in place
- verify_integrity : bool (default True)
if True, checks that levels and codes are compatible
Returns: - new index (of same type and class…etc)
Examples
>>> idx = pd.MultiIndex.from_tuples([(1, u'one'), (1, u'two'), (2, u'one'), (2, u'two')], names=['foo', 'bar']) >>> idx.set_levels([['a','b'], [1,2]]) MultiIndex(levels=[[u'a', u'b'], [1, 2]], codes=[[0, 0, 1, 1], [0, 1, 0, 1]], names=[u'foo', u'bar']) >>> idx.set_levels(['a','b'], level=0) MultiIndex(levels=[[u'a', u'b'], [u'one', u'two']], codes=[[0, 0, 1, 1], [0, 1, 0, 1]], names=[u'foo', u'bar']) >>> idx.set_levels(['a','b'], level='bar') MultiIndex(levels=[[1, 2], [u'a', u'b']], codes=[[0, 0, 1, 1], [0, 1, 0, 1]], names=[u'foo', u'bar']) >>> idx.set_levels([['a','b'], [1,2]], level=[0,1]) MultiIndex(levels=[[u'a', u'b'], [1, 2]], codes=[[0, 0, 1, 1], [0, 1, 0, 1]], names=[u'foo', u'bar'])