pandas.api.typing.DataFrameGroupBy.cummin#
- DataFrameGroupBy.cummin(numeric_only=False, skipna=True, **kwargs)[source]#
Cumulative min for each group.
Returns a same-sized object where each value is replaced by the minimum of all preceding values in its group.
- Parameters:
- numeric_onlybool, default False
Include only float, int or boolean data.
- skipnabool, default True
Exclude NA/null values. If an entire row/column is NA, the result will be NA.
- **kwargsdict, optional
Additional keyword arguments to be passed to the function.
Deprecated since version 3.1.0: Passing
**kwargsto GroupBy.cummin is deprecated and will be removed in a future version of pandas.
- Returns:
- Series or DataFrame
Cumulative min for each group. Same object type as the caller.
See also
Series.cumminApply function cummin to a Series.
DataFrame.cumminApply function cummin to each row or column of a DataFrame.
Examples
For SeriesGroupBy:
>>> lst = ["a", "a", "a", "b", "b", "b"] >>> ser = pd.Series([1, 6, 2, 3, 0, 4], index=lst) >>> ser a 1 a 6 a 2 b 3 b 0 b 4 dtype: int64 >>> ser.groupby(level=0).cummin() a 1 a 1 a 1 b 3 b 0 b 0 dtype: int64
For DataFrameGroupBy:
>>> data = [[1, 0, 2], [1, 1, 5], [6, 6, 9]] >>> df = pd.DataFrame( ... data, columns=["a", "b", "c"], index=["snake", "rabbit", "turtle"] ... ) >>> df a b c snake 1 0 2 rabbit 1 1 5 turtle 6 6 9 >>> df.groupby("a").groups {1: ['snake', 'rabbit'], 6: ['turtle']} >>> df.groupby("a").cummin() b c snake 0 2 rabbit 0 2 turtle 6 9