pandas.MultiIndex.set_labels¶
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MultiIndex.
set_labels
(labels, level=None, inplace=False, verify_integrity=True)[source]¶ Set new labels on MultiIndex. Defaults to returning new index.
Parameters: labels : sequence or list of sequence
new labels to apply
level : int, level name, or sequence of int/level names (default None)
level(s) to set (None for all levels)
inplace : bool
if True, mutates in place
verify_integrity : bool (default True)
if True, checks that levels and labels are compatible
Returns: - new index (of same type and class…etc)
Examples
>>> idx = MultiIndex.from_tuples([(1, u'one'), (1, u'two'), (2, u'one'), (2, u'two')], names=['foo', 'bar']) >>> idx.set_labels([[1,0,1,0], [0,0,1,1]]) MultiIndex(levels=[[1, 2], [u'one', u'two']], labels=[[1, 0, 1, 0], [0, 0, 1, 1]], names=[u'foo', u'bar']) >>> idx.set_labels([1,0,1,0], level=0) MultiIndex(levels=[[1, 2], [u'one', u'two']], labels=[[1, 0, 1, 0], [0, 1, 0, 1]], names=[u'foo', u'bar']) >>> idx.set_labels([0,0,1,1], level='bar') MultiIndex(levels=[[1, 2], [u'one', u'two']], labels=[[0, 0, 1, 1], [0, 0, 1, 1]], names=[u'foo', u'bar']) >>> idx.set_labels([[1,0,1,0], [0,0,1,1]], level=[0,1]) MultiIndex(levels=[[1, 2], [u'one', u'two']], labels=[[1, 0, 1, 0], [0, 0, 1, 1]], names=[u'foo', u'bar'])