pandas.Series.nlargest¶
-
Series.
nlargest
(n=5, keep='first')[source]¶ Return the largest n elements.
Parameters: n : int
Return this many descending sorted values
keep : {‘first’, ‘last’}, default ‘first’
Where there are duplicate values: -
first
: take the first occurrence. -last
: take the last occurrence.Returns: top_n : Series
The n largest values in the Series, in sorted order
See also
Notes
Faster than
.sort_values(ascending=False).head(n)
for small n relative to the size of theSeries
object.Examples
>>> import pandas as pd >>> import numpy as np >>> s = pd.Series(np.random.randn(10**6)) >>> s.nlargest(10) # only sorts up to the N requested 219921 4.644710 82124 4.608745 421689 4.564644 425277 4.447014 718691 4.414137 43154 4.403520 283187 4.313922 595519 4.273635 503969 4.250236 121637 4.240952 dtype: float64