pandas.MultiIndex.is_lexsorted¶
-
MultiIndex.is_lexsorted()[source]¶ Return True if the codes are lexicographically sorted.
- Returns
- bool
Examples
In the below examples, the first level of the MultiIndex is sorted because a<b<c, so there is no need to look at the next level.
>>> pd.MultiIndex.from_arrays([['a', 'b', 'c'], ['d', 'e', 'f']]).is_lexsorted() True >>> pd.MultiIndex.from_arrays([['a', 'b', 'c'], ['d', 'f', 'e']]).is_lexsorted() True
In case there is a tie, the lexicographical sorting looks at the next level of the MultiIndex.
>>> pd.MultiIndex.from_arrays([[0, 1, 1], ['a', 'b', 'c']]).is_lexsorted() True >>> pd.MultiIndex.from_arrays([[0, 1, 1], ['a', 'c', 'b']]).is_lexsorted() False >>> pd.MultiIndex.from_arrays([['a', 'a', 'b', 'b'], ... ['aa', 'bb', 'aa', 'bb']]).is_lexsorted() True >>> pd.MultiIndex.from_arrays([['a', 'a', 'b', 'b'], ... ['bb', 'aa', 'aa', 'bb']]).is_lexsorted() False