pandas.array¶
-
pandas.
array
(data, dtype=None, copy=True)[source]¶ Create an array.
New in version 0.24.0.
- Parameters
- dataSequence of objects
The scalars inside data should be instances of the scalar type for dtype. It’s expected that data represents a 1-dimensional array of data.
When data is an Index or Series, the underlying array will be extracted from data.
- dtypestr, np.dtype, or ExtensionDtype, optional
The dtype to use for the array. This may be a NumPy dtype or an extension type registered with pandas using
pandas.api.extensions.register_extension_dtype()
.If not specified, there are two possibilities:
When data is a
Series
,Index
, orExtensionArray
, the dtype will be taken from the data.Otherwise, pandas will attempt to infer the dtype from the data.
Note that when data is a NumPy array,
data.dtype
is not used for inferring the array type. This is because NumPy cannot represent all the types of data that can be held in extension arrays.Currently, pandas will infer an extension dtype for sequences of
Scalar Type
Array Type
pandas.arrays.FloatingArray
For all other cases, NumPy’s usual inference rules will be used.
Changed in version 1.0.0: Pandas infers nullable-integer dtype for integer data, string dtype for string data, and nullable-boolean dtype for boolean data.
Changed in version 1.2.0: Pandas now also infers nullable-floating dtype for float-like input data
- copybool, default True
Whether to copy the data, even if not necessary. Depending on the type of data, creating the new array may require copying data, even if
copy=False
.
- Returns
- ExtensionArray
The newly created array.
- Raises
- ValueError
When data is not 1-dimensional.
See also
numpy.array
Construct a NumPy array.
Series
Construct a pandas Series.
Index
Construct a pandas Index.
arrays.PandasArray
ExtensionArray wrapping a NumPy array.
Series.array
Extract the array stored within a Series.
Notes
Omitting the dtype argument means pandas will attempt to infer the best array type from the values in the data. As new array types are added by pandas and 3rd party libraries, the “best” array type may change. We recommend specifying dtype to ensure that
the correct array type for the data is returned
the returned array type doesn’t change as new extension types are added by pandas and third-party libraries
Additionally, if the underlying memory representation of the returned array matters, we recommend specifying the dtype as a concrete object rather than a string alias or allowing it to be inferred. For example, a future version of pandas or a 3rd-party library may include a dedicated ExtensionArray for string data. In this event, the following would no longer return a
arrays.PandasArray
backed by a NumPy array.>>> pd.array(['a', 'b'], dtype=str) <PandasArray> ['a', 'b'] Length: 2, dtype: str32
This would instead return the new ExtensionArray dedicated for string data. If you really need the new array to be backed by a NumPy array, specify that in the dtype.
>>> pd.array(['a', 'b'], dtype=np.dtype("<U1")) <PandasArray> ['a', 'b'] Length: 2, dtype: str32
Finally, Pandas has arrays that mostly overlap with NumPy
When data with a
datetime64[ns]
ortimedelta64[ns]
dtype is passed, pandas will always return aDatetimeArray
orTimedeltaArray
rather than aPandasArray
. This is for symmetry with the case of timezone-aware data, which NumPy does not natively support.>>> pd.array(['2015', '2016'], dtype='datetime64[ns]') <DatetimeArray> ['2015-01-01 00:00:00', '2016-01-01 00:00:00'] Length: 2, dtype: datetime64[ns]
>>> pd.array(["1H", "2H"], dtype='timedelta64[ns]') <TimedeltaArray> ['0 days 01:00:00', '0 days 02:00:00'] Length: 2, dtype: timedelta64[ns]
Examples
If a dtype is not specified, pandas will infer the best dtype from the values. See the description of dtype for the types pandas infers for.
>>> pd.array([1, 2]) <IntegerArray> [1, 2] Length: 2, dtype: Int64
>>> pd.array([1, 2, np.nan]) <IntegerArray> [1, 2, <NA>] Length: 3, dtype: Int64
>>> pd.array([1.1, 2.2]) <FloatingArray> [1.1, 2.2] Length: 2, dtype: Float64
>>> pd.array(["a", None, "c"]) <StringArray> ['a', <NA>, 'c'] Length: 3, dtype: string
>>> pd.array([pd.Period('2000', freq="D"), pd.Period("2000", freq="D")]) <PeriodArray> ['2000-01-01', '2000-01-01'] Length: 2, dtype: period[D]
You can use the string alias for dtype
>>> pd.array(['a', 'b', 'a'], dtype='category') ['a', 'b', 'a'] Categories (2, object): ['a', 'b']
Or specify the actual dtype
>>> pd.array(['a', 'b', 'a'], ... dtype=pd.CategoricalDtype(['a', 'b', 'c'], ordered=True)) ['a', 'b', 'a'] Categories (3, object): ['a' < 'b' < 'c']
If pandas does not infer a dedicated extension type a
arrays.PandasArray
is returned.>>> pd.array([1 + 1j, 3 + 2j]) <PandasArray> [(1+1j), (3+2j)] Length: 2, dtype: complex128
As mentioned in the “Notes” section, new extension types may be added in the future (by pandas or 3rd party libraries), causing the return value to no longer be a
arrays.PandasArray
. Specify the dtype as a NumPy dtype if you need to ensure there’s no future change in behavior.>>> pd.array([1, 2], dtype=np.dtype("int32")) <PandasArray> [1, 2] Length: 2, dtype: int32
data must be 1-dimensional. A ValueError is raised when the input has the wrong dimensionality.
>>> pd.array(1) Traceback (most recent call last): ... ValueError: Cannot pass scalar '1' to 'pandas.array'.