pandas.core.groupby.SeriesGroupBy.sum#
- SeriesGroupBy.sum(numeric_only=False, min_count=0, engine=None, engine_kwargs=None)[source]#
- Compute sum of group values. - Parameters:
- numeric_onlybool, default False
- Include only float, int, boolean columns. - Changed in version 2.0.0: numeric_only no longer accepts - None.
- min_countint, default 0
- The required number of valid values to perform the operation. If fewer than - min_countnon-NA values are present the result will be NA.
- enginestr, default None None
- 'cython': Runs rolling apply through C-extensions from cython.
- 'numba'Runs rolling apply through JIT compiled code from numba.
- Only available when - rawis set to- True.
 
- None: Defaults to- 'cython'or globally setting- compute.use_numba
 
- engine_kwargsdict, default None None
- For - 'cython'engine, there are no accepted- engine_kwargs
- For 'numba'engine, the engine can acceptnopython,nogil
- and - paralleldictionary keys. The values must either be- Trueor- False. The default- engine_kwargsfor the- 'numba'engine is- {'nopython': True, 'nogil': False, 'parallel': False}and will be applied to both the- funcand the- applygroupby aggregation.
 
- For 
 
 
- Returns:
- Series or DataFrame
- Computed sum of values within each group. 
 
 - Examples - For SeriesGroupBy: - >>> lst = ['a', 'a', 'b', 'b'] >>> ser = pd.Series([1, 2, 3, 4], index=lst) >>> ser a 1 a 2 b 3 b 4 dtype: int64 >>> ser.groupby(level=0).sum() a 3 b 7 dtype: int64 - For DataFrameGroupBy: - >>> data = [[1, 8, 2], [1, 2, 5], [2, 5, 8], [2, 6, 9]] >>> df = pd.DataFrame(data, columns=["a", "b", "c"], ... index=["tiger", "leopard", "cheetah", "lion"]) >>> df a b c tiger 1 8 2 leopard 1 2 5 cheetah 2 5 8 lion 2 6 9 >>> df.groupby("a").sum() b c a 1 10 7 2 11 17