pandas.MultiIndex.set_codes

MultiIndex.set_codes(codes, level=None, inplace=None, verify_integrity=True)[source]

Set new codes on MultiIndex. Defaults to returning new index.

New in version 0.24.0: New name for deprecated method set_labels.

Parameters
codessequence or list of sequence

New codes to apply.

levelint, level name, or sequence of int/level names (default None)

Level(s) to set (None for all levels).

inplacebool

If True, mutates in place.

Deprecated since version 1.2.0.

verify_integritybool, default True

If True, checks that levels and codes are compatible.

Returns
new index (of same type and class…etc) or None

The same type as the caller or None if inplace=True.

Examples

>>> idx = pd.MultiIndex.from_tuples(
...     [(1, "one"), (1, "two"), (2, "one"), (2, "two")], names=["foo", "bar"]
... )
>>> idx
MultiIndex([(1, 'one'),
    (1, 'two'),
    (2, 'one'),
    (2, 'two')],
   names=['foo', 'bar'])
>>> idx.set_codes([[1, 0, 1, 0], [0, 0, 1, 1]])
MultiIndex([(2, 'one'),
            (1, 'one'),
            (2, 'two'),
            (1, 'two')],
           names=['foo', 'bar'])
>>> idx.set_codes([1, 0, 1, 0], level=0)
MultiIndex([(2, 'one'),
            (1, 'two'),
            (2, 'one'),
            (1, 'two')],
           names=['foo', 'bar'])
>>> idx.set_codes([0, 0, 1, 1], level='bar')
MultiIndex([(1, 'one'),
            (1, 'one'),
            (2, 'two'),
            (2, 'two')],
           names=['foo', 'bar'])
>>> idx.set_codes([[1, 0, 1, 0], [0, 0, 1, 1]], level=[0, 1])
MultiIndex([(2, 'one'),
            (1, 'one'),
            (2, 'two'),
            (1, 'two')],
           names=['foo', 'bar'])